9m^2+14m+4=0

Solution for 9m^2+14m+4=0 equation:

9m^2+14m+4=0

a = 9; b = 14; c = +4;
Δ = b2-4ac
Δ = 142-4·9·4
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{13}}{2*9}=\frac{-14-2\sqrt{13}}{18}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{13}}{2*9}=\frac{-14+2\sqrt{13}}{18}
$